The V5+ of V2O5 can oxide Co2+ of Co(OH)2 into Co3+, resulting in in situ formations of CoOOH species favorable to the OER process. In situ Raman also investigates that the OH– species are inserted easily into the interlayer of Co(OH)2 of (Co(OH)2/V2O5) than that of pure Co(OH)2, suggesting good OER performance.
Instead of giving you the answer, let me show you how to do this type. When they get a little complicated, I like to break them up into half reactions. Co(OH)2 ==> Co(OH)3 . It's obvious that Co changes from +2 to +3 so we need a one electron on the right and we need to balance the OH^- which we can do directly. Co(OH)2 + OH^- ==> Co(OH)3 + e Note that the equation balances a. elements. b. electron change. c. charge. Next half cell. O2^-2 ==> OH^- First we place a 2 coefficient for OH^- and compute changes. O2^-2 ==> 2OH^- Now O2^-2 has changed from -2 on the left (for both oxygens) to -4 on the right (for both oxygens) (which is why I stuck that two before starting any of this--we must compare the same number of oxygen atoms). So the change in electrons is -2 to -4 or +2; O2^-2 + 2e ==> 2OH^- The charge on the left is -2, on the right is -4 so we must add 2OH^- to the right. O2^-2 + 2e ==> 4OH^- and add water to the left. 2H2O + O2^-2 + 2e ==> 4OH^- a. by atoms. yes. b. by electron change. yes. c. by charge. yes. Now note the first half reaction changes by 1 e, the second half reaction by 2e; therefore, we multiply the first one by 2 and second one by 1 and add. You should do this but you should get this. 2Co(OH)2 + 2OH^- + O2^-2 + 2H2O ==>2Co(OH)3 + 4OH^- We can cancel 2OH&- to make it 2Co(OH)2 + O2^-2 + 2H2O ==>2Co(OH)3 + 2OH^- Now we can add Na^+ to the left for the Na2O2 and the right for the NaOH in the problem. 2Co(OH)2 + Na2O2 + 2H2O ==> 2Co(OH)3 + 2NaOH
C 2 H 5 OH + O 2 → CH 3 COOH + H 2 O. 2. Điều kiện phản ứng Phản ứng C2H5OH ra CH3COOH. Điều kiện khác: men giấm. 3. Cách thực hiện phản ứng Phản ứng C2H5OH ra CH3COOH. Để sản xuất giấm ăn, người ta thường dùng phương pháp lên men dung dịch rượu etylic loãng. 4. Thông tin thêm
Step 3: Verify that the equation is balanced. Since there are an equal number of atoms of each element on both sides, the equation is balanced. C 6 H 12 O 6 + 6 O 2 = 6 CO 2 + 6 H 2 O. Balance the reaction of C6H12O6 + O2 = CO2 + H2O using this chemical equation balancer!
We thus propose SiO2-supported Co(OH)2 nanoparticles (NPs) as excellent catalysts for the simultaneous scrubbing of polluting SOX/NOX gases in flue gases using atmospheric O2 as the oxidation
Step 3: Verify that the equation is balanced. Since there are an equal number of atoms of each element on both sides, the equation is balanced. 2 C 5 H 11 OH + 15 O 2 = 10 CO 2 + 12 H 2 O. Balance the reaction of C5H11OH + O2 = CO2 + H2O using this chemical equation balancer!
2 (g) → CO 2 (g) ∆H = –393.5 kJ (4) 2CO (g) + O AgCl (s) –127.1 Ca(OH) 2 (s) –986.1 K 3PO 4 (aq) –2002.9. AgNO 3 (aq) –100.7 Ca(OH) 2 (aq) –1002.9
RwvNCYh. 371 385 282 101 305 147 54 135 30
co oh 2 o2
